Sama penjelasannya ya^^ bagi yang cuma mau poin plis jgn jawab:(

3x + 5y = b^(blog4)
3x + 5y = 4

x - 3y = (216)^(1/3)
x - 3y = 6

x - 3y = 6
x = 6 + 3y

3x + 5y = 4
3(6 + 3y) + 5y = 4
18 + 9y + 5y = 4
14y = -14
y = -1

x = 6 + 3y
x = 6 - 3
x = 3

3loga = x + y
3loga = 3 - 1
3loga = 2

a = 3^2 = 9

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Misal, 3^x = a, maka

3log(4(3^x) - 7) = -1 + 3log(3^(2x) + 6)
3log(4a - 7) = 3log3^(-1) + 3log(a^2 + 6)
3log(4a - 7) = 3log(3^(-1)(a^2 + 6))
3log(4a - 7) = 3log((a^2)/3 + 2)

4a - 7 = (a^2)/3 + 2
12a - 21 = a^2 + 6
a^2 - 12a + 27 = 0
(a - 9)(a - 3) = 0

a = 9 atau a = 3
misal, a = 9, maka 3^x = 9
x = 2

misal, a = 3, maka 3^x = 3
x = 1

sehingga p + q = 2 + 1 = 3