tolong kerjakan ya no 1 dan 2 besok dikumpulin soalnya Terimakasih

1.5 1/2 = 11/2 × 3 =33/2
7 3/4 = 31/4
33/2-31/4=35/4= 8 3/4
jadi panjang tali yg masih tersisa 8 3/4 m
2.7 1/2=15/2
15/2-3/4=27/4:3/1=225/100=2,25
jadi panjang tiap potong kawat 2,25 m
#semoga membantu & maaf kalo salah#

[tex]no1 \\ 3 \times 5 \frac{1}{2} = \frac{3}{1} \times \frac{11}{2} = \frac{33}{2} = 16 \frac{1}{2} \\ 16 \frac{1}{2} - 7 \frac{3}{4} = (15 - 7) + ( \frac{3}{2} - \frac{3}{4} ) = 8 + ( \frac{6}{4} - \frac{3}{4} ) = 8 \frac{3}{4} \\ \\ no \: 2 \\ 7 \frac{1}{2} - \frac{3}{4} = 6 \frac{6}{4} - \frac{3}{4} = 6 \frac{3}{4} \\ 6 \frac{3}{4} \div 3 = \frac{27}{4} \times \frac{1}{3} = \frac{27}{12} = 2 \frac{3}{12} = 2 \frac{1}{4} [/tex]