tolong dong isi soal ini

Mapel : Matematika
Materi : Bilangan Akar 

[tex]1.)\ \frac{5}{3- \sqrt{3}}=....\\\\=\frac{5}{3-\sqrt{3}}\times\frac{3+\sqrt{3}}{3+\sqrt{3}}\\\\=\frac{5\times(3+\sqrt{3})}{(3-\sqrt{3})(3+\sqrt{3})}\\\\=\frac{15 + 5\sqrt{3}}{3^2-(\sqrt{3})^2}\\\\=\frac{15+5\sqrt{3}}{9-3}\\\\=\frac{15+5\sqrt{3}}{6}\\\\=\frac{15}{6}+\frac{5\sqrt{3}}{6}\\\\=\boxed{2\frac{1}{2}+\frac{5}{6}\sqrt{3}}[/tex]

[tex]2.)\ \frac{\sqrt{5}}{5+\sqrt{7}}=....\\\\=\frac{\sqrt{5}}{5+\sqrt{7}}\times\frac{5-\sqrt{7}}{5-\sqrt{7}}\\\\=\frac{(\sqrt{5})(5-\sqrt{7})}{(5+\sqrt{7})(5-\sqrt{7})}\\\\=\frac{5\sqrt{5}-(\sqrt{5})(\sqrt{7})}{(5)^2-(\sqrt{7})^2}\\\\=\frac{5\sqrt{5}-\sqrt{35}}{25-7}\\\\=\boxed{\frac{5\sqrt{5}-\sqrt{35}}{18}}[/tex]

[tex]3.)\ \frac{4\sqrt{5}}{\sqrt{4}+3}=....\\\\=\frac{4\sqrt{5}}{2+3}\\\\=\frac{4\sqrt{5}}{5}\\\\=\boxed{\frac{4}{5}\sqrt{5}}[/tex]

[tex]4.)\ \frac{1-3\sqrt{2}}{4+\sqrt{3}}=....\\\\=\frac{1-3\sqrt{2}}{4+\sqrt{3}}\times\frac{4-\sqrt{3}}{4-\sqrt{3}}\\\\=\frac{(1-3\sqrt{2})(4-\sqrt{3})}{(4+\sqrt{3})(4-\sqrt{3})}\\\\=\frac{4-12\sqrt{2}-\sqrt{3}+3\sqrt{6}}{4^2-(\sqrt{3})^2}\\\\=\frac{4-12\sqrt{2}-\sqrt{3}+3\sqrt{6}}{16-3}\\\\=\boxed{\frac{4-12\sqrt{2}-\sqrt{3}+3\sqrt{6}}{13}}[/tex]

[tex]5.)\ \frac{2\sqrt{5}}{3-\sqrt{11}}=....\\\\=\frac{2\sqrt{5}}{3-\sqrt{11}}\times\frac{3+\sqrt{11}}{3+\sqrt{11}}\\\\=\frac{(2\sqrt{5})(3+\sqrt{11})}{(3-\sqrt{11})(3+\sqrt{11})}\\\\=\frac{6\sqrt{5}+2\sqrt{55}}{3^2-(\sqrt{11})^2}\\\\=\frac{6\sqrt{5}+2\sqrt{55}}{9-11}\\\\=\frac{6\sqrt{5}+2\sqrt{55}}{-2}\\\\=\frac{6}{-2}\sqrt{5}+\frac{2}{-2}\sqrt{55}\\\\=\boxed{-3\sqrt{5}-\sqrt{55}}[/tex]

***Semoga Terbantu***