tolong dibantu mohon
Matematika
delia178
Pertanyaan
tolong dibantu mohon
1 Jawaban
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1. Jawaban PersatuanWibu
6) sin 60 = 2√3 / AC 7) cos 60 = BD / 36
√3 0,5 = BD / 36
------ = 2√3 / AC BD = 0,5 x 36
2 = 18 cm
2 sin 60 = AB / 36
------ x (2√3) = AC √3
√3 ----- = AB / 36
4 cm = AC 2
AB = 18√3 cm
cos 45 = AD / AC
√2 tan30 = (18√3) : (BD + DC)
---- = AD / 4 0,5
2 ----- = 18√3 : (18 + DC)
√3/2
√2 1
----- : ----- = AD 1 18√3
2 4 ---- = -----------
√3 18 + DC
AD = 2√2 cm
18 + DC = 18√3 x√3
DC = 18 x 3 - 18
DC = 36 cm