tentukan nilai minimum dari fungsi kuadrat f(x)=x kuadrat+6x+2.....

Kelas 10 Matematika
Bab Persamaan Kuadrat

f(x) = x² + 6x + 2
a = 1; b = 6; c = 2

Sumbu simetri
= -b/2a
= -6/(2 . 1)
= -3

f(-3) = (-3)² + 6 . (-3) + 2
f(-3) = 9 - 18 + 2
f(-3) = -7

Nilai minimum = -7