3 - √8 / 3 + √8 = dibantu yah

[tex] \frac{3- \sqrt{8} }{3+ \sqrt{8} } = \frac{3- \sqrt{8} }{3+ \sqrt{8} } . \frac{3- \sqrt{8} }{3- \sqrt{8} } = \frac{9-3 \sqrt{8}- 3\sqrt{8}+8 }{9-8} = \frac{17-6 \sqrt{8} }{1} = 17-6 \sqrt{8} [/tex]