persamaan garis yang melalui titik (5,-5) dan (-5,1) adalah

x1 = 5, x2 = -5
y1 = -5, y2 = 1

persamaan garisnya adalah
[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - ( - 5)}{1 - ( - 5)} = \frac{x - 5}{ - 5 - 5} \\ \frac{y + 5}{6} = \frac{x - 5}{ - 10} \\ - 10(y + 5) = 6(x - 5) \\ [/tex]
-10y - 50 = 6x - 30
-10y = 6x - 30 + 50
-10y = 6x + 20
6x + 10y + 20 = 0

x1=5 x2=-5 y1=-5 y2=1


(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
(y+5)/(1+5)=(x-5)/(-5-5)
(y+5)/6=(x-5)/-10
6x-30=-10y-50
6x+10y=-20