jawablah soal berikut nn112°F=...°C
Matematika
kevinhutapea
Pertanyaan
jawablah soal berikut
nn112°F=...°C
nn112°F=...°C
2 Jawaban
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1. Jawaban Takamori37
[tex]112^oF = \frac{5}{9}(112-32)^oC \\ 112^oF = \frac{5}{9}\times 90^oC \\ 112^oF = 50^oC \\ [/tex] -
2. Jawaban Hasnainitp
112 - 32 = 80 . 5 / 9 x 80 =