suatu deret geometri 3+12+48+...jumlah 8suku pertama adalah

jwab
deret geometri

3  + 12 + 48 +...
a= 3
r = 12/3 =4

s8 = a( r⁸  -1)/ ( r - 1)
s8 = 3 (4⁸ -1) / (4-1)
s8 = 3/3 (65.535)
s8 = 65.535

Sn=a(r^n-1)/(r-1)
=3(4^8-1)/(4-1)
=3(65535)/(3)
=65535