hitung PH 100mL larutan terdapat 0,0001 mol H2SO4

Diketahui :
Volume = 100mL
mol = 0,0001 mol H2SO4
Ditanya : pH?
Jawab :
M = n/Volume
M = 10^-4 / 100
M = 10^-6

[H+] = Ma x a
[H+] = 10^-6 x 2
[H+] = 2x10^-6

pH = -log[H+]
pH = -log2x10^-6
pH = 6-log2

Semoga membantu.