diketahui f(x) = 1/x+2 dan g(x)= x+2/x-3. tentukan (f o g ) -1 (x)

[tex](fog) = \frac{1}{g(x) + 2} \\ = \frac{1}{ \frac{x + 2}{x - 3} + 2 } \\ = \frac{1}{ \frac{x + 2 + 2x - 6}{ x - 3} } \\ = \frac{x - 3}{3x - 4} [/tex]
[tex]jika \: f(x) = \frac{ax + b}{cx + d} \\maka \: f(x) {}^{ - 1} = \frac{ - dx + b}{cx - a} [/tex]
[tex](fog) {}^{ - 1} (x) = \frac{4x - 3}{3x - 1} [/tex]
semoga membantu......

-3x-1/x+2
semoga membantu