Di jwb...... Yaaaaa...... . .

Mapel : Matematika
Materi : Akar Pangkat

Soal No. 7
[tex]=\sqrt[5]{81^2}\\\\=\sqrt[5]{(3^4)^2}\\\\=\sqrt[5]{(3^8)}\\\\=\sqrt[5]{(3^5\times3^3)}\\\\=\sqrt[5]{(3^5)}\times\sqrt[5]{(3^3)}\\\\=\sqrt[5]{(3^5)}\times\sqrt[5]{9}\\\\=3^{\frac{5}{5}}\times9^{\frac{1}{5}}\\\\=3\times9^{\frac{1}{5}}[/tex]

Soal No. 8

[tex]=((8\sqrt{3})x+\sqrt{6})((5\sqrt{3})x+\sqrt{2})\\\\=((8\sqrt{3})x)((5\sqrt{3})x)+(\sqrt{6})((5\sqrt{3})x)+((8\sqrt{3})x)(\sqrt{2})+(\sqrt{6})(\sqrt{2})\\\\=(8\times5).(\sqrt{3})^2.(x)^2+((5\sqrt{3})(\sqrt{6}))x+(8\sqrt{6})x+(\sqrt{12})\\\\=(40\times3)x^2+ ((5\sqrt{3}+8)(\sqrt{6}))x+ \sqrt{(4\times3)}\\\\=120x^2+ ((5\sqrt{3}+8)(\sqrt{6}))x+2\sqrt{3}[/tex]

Soal No. 9

Luas = Panjang × Lebar
Luas = 10.a³ × 4.a³
Luas = (10 × 4)(a³)²

Luas = 40.a⁶

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