tolong bantu ya besok di kumpul tolong ya pake cara

3 sqrt(3).4² -5 sqrt(3).4² + 6 sqrt(3).4² = 4 sqrt(3).4² (d)


*sqrt(3) mksudnya akar tiga

[tex]3 {(4)}^{ \frac{2}{3} } - 5 \sqrt[3]{ {4}^{2} } + 6 {(4)}^{ \frac{2}{3} } \\ = 3 \sqrt[3]{ {4}^{2} } - 5 \sqrt[3]{ {4}^{2} } + 6 \sqrt[3]{ {4}^{2} } \\ = 4 \sqrt[3]{ {4}^{2} } [/tex]
jawabannya D..