Mohon bantuannya. Nilai f(x), jika a. f'(x) = 6x^2 - 2x + 5, f(0)=5 b. f'(x) = 1/2x^2 , f(3) = 7/6

jawab

1.
F(x) = ∫ 6x² -2x + 5 dx
F(x)= 2x³ - x² + 5x + c
f(0)= 5 --> c= 5
F(x) = 2x³ - x² + 5x + 5

2.
F(x) = ∫ 1/2x² dx
F(x)=  1/2. 1/3 x³ + c
F(x)=  1/6 x³+ c
F(3) = 7/6 --> 27/6 + c = 7/6
c = 20/6
F(x) = 1/6 x³ + 20/6
F(x) = 1/6 (x³ + 20)