Tentukan nilai x y,dan z 2x+y+z=8 3x-y+2z=17 4x+2y-z=1 dengan caranya

pers 1
2x+y+z= 8
3x-y+2z= 17
----------------- +
5x+3z = 25

pers 2
3x-y+2z = 17 x2
4x+2y-z= 1 x1
----------------
6x-2y+4z = 34
4x+2y - z = 1
--------------------- +
10x-3z= 35

eliminasi lg
5x+3z= 25
10x-3z = 35
------------------+
15x = 60
x = 4
subsitusi
10x-3z= 35
10(4)-3z= 35
40-3z= 35
- 3z = 35-40
-3z = -5
z = 5/3

4x+2y-z = 1
4(4)+ 2(5/3) - z = 1
16+10/3 - z = 1
[tex] \frac{16}{1} + \frac{10}{3} + z = 1[/tex]
[tex] \frac{48 + 10}{3} = \frac{58}{3} + z = 1[/tex]
[tex]z = 1 - \frac{58}{3} [/tex]
[tex]z = \frac{1}{1} - \frac{58}{3} = \frac{3 - 58}{3} = \frac{55}{3} [/tex]