berapakah pH larutan asam formiat 0,01 M. Ka= 1.96*0.0004
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Maranatha11
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berapakah pH larutan asam formiat 0,01 M. Ka= 1.96*0.0004
1 Jawaban
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1. Jawaban ovin88
[H+]=√0.01×1.96×10^-4
[H+]= 1.4 × 10^-3
pH = -log[H+]
= -log 1.4×10^-4
= 4-log 1.4
= 3.398