bisa dibantu tentukam turumam fungsinya, ?

- Turunan Fungsi -

f(x) = x²-2x
f'(x) = lim f(x+h) -f(h) / h
f'(x) = lim [ {(x+h)² - 2(x+h)} - ( x² - 2x )] / h
f'(x) = lim [ x²+2xh+h²-2x-2h-x²+2x ] / h
f'(x) = lim [x²-x²+2xh-2x+2x-2h+h² ] / h
f'(x) = lim [ 2xh -2h+h²] / h
f'(x) = lim [ h (2x-2+h)] /h
f'(x) = lim 2x-2+h
f'(x) = 2x-2

note: semua limit itu lim h mendekati 0

semoga membantu
-vin