Matematika

Pertanyaan

carilah solusi ( x , ) bil. real untuk setiap sistem persamaan kuadrat - kuadrat berikut :
1. x^2 + y^2 = 1 dan y = 3x^2
2. 2x^2 + y^2 = 17 dan x^2 + 2y^2 = 22

1 Jawaban

  • 1.
    [tex]x^2+y^2=1 \\ y=3x^2 \\ x^2=\frac{1}{3}y \\ \\ \frac{1}{3}y+y^2=1 \\ y+3y^2=3 \\ 3y^2+y-3=0 \\ $Rumus ABC, didapat:$ \\ y=\frac{-1\pm\sqrt{37}}{6} \\ 3x^2=\frac{-1\pm\sqrt{37}}{6} \\ x=\sqrt{\frac{-1\pm\sqrt{37}}{18}} \\ \\ $Maka:$ \\ HP=\{(x,y)|(\sqrt{\frac{-1-\sqrt{37}}{18}}),(\frac{-1-\sqrt{37}}{6}),(\sqrt{\frac{-1+\sqrt{37}}{18}}),(\frac{-1+\sqrt{37}}{6})\}[/tex]

    2.
    [tex]2x^2+y^2=17 \\ y^2=17-2x^2 \\ \\ x^2+2y^2=22 \\ x^2+2(17-2x^2)=22 \\ x^2+34-4x^2=22 \\ -3x^2=-12 \\ x^2=4 \\ x=\pm 2 \\ \\ 4+2y^2=22 \\ 2y^2=18 \\ y^2=9 \\ y=\pm 3 \\ \\ HP=\{(x,y)|(-2,-3),(2,3)\}[/tex]

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