10 per 5-akar2 plisss jawab!!!!!!!..

Kelas 9 Matematika
Bab Akar dan Pangkat

10/(5 - √2)
= 10/(5 - √2) . (5 + √2)/(5 + √2)
= (50 + 10√2)/(5² - √2²)
= (50 + 10√2) / (25 - 2)
= (50 + 10√2)/23

[tex] = \frac{10}{5 - \sqrt{2} } \\ = \frac{10}{5 - \sqrt{2} } \times \frac{5 + \sqrt{2} }{5 + \sqrt{2} } \\ = \frac{50 + 10 \sqrt{2} }{25 - 2} \\ = \frac{50 + 10 \sqrt{2} }{23} \\ = \frac{50}{23} +\frac{10}{23} \sqrt{2} [/tex]

Semoga membantu...
Trimakasih