3 akar 6/akar 3 + akar 5 [tex]3 \sqrt{6} \div \sqrt{3} + \sqrt{5 } [/tex]
Matematika
zafran16
Pertanyaan
3 akar 6/akar 3 + akar 5
[tex]3 \sqrt{6} \div \sqrt{3} + \sqrt{5 } [/tex]
[tex]3 \sqrt{6} \div \sqrt{3} + \sqrt{5 } [/tex]
2 Jawaban
-
1. Jawaban Yudhitia120202
(2√3 + 5√6)(3√3 -4√6)
=18 - 8√18 + 15√18 - 120
=√18 - 8√18 + 15√18 -2√30
=8√18 - 2√30
= 12 - 2√30 -
2. Jawaban isnani18
3√6 / (√3 + √5)
= 3√6/(√3 + √5) x (√3 - √5)/(√3 - √5)
= (3√18 - 3√30) / (3 - 5)
= (3√9√2 - 3√30) / (-2)
= (9√2 - 3√30) / (-2)
= 3(3√2 - √30) / (-2)
= -3/2 (3√2 - √30)