jika 7 log 3 = a dan 3 log 2 = b, nilai 48 log 84 =

jawab
Logaritma
7'log 3 = a
3'log 2 = b

7'log3 . 3'log 2 = a.b
7'log 2 = ab

(48)'log 84 = 7'log 84/7'log 48
= (7'log 7.2². 3) / (7'log 2⁴. 3)

= (7'log 7 + 2. 7'log 2 + 7'log 3) / (4. 7'log 2 + 7'log 3)
= (1 + 2ab + a) / (4 ab  + a)