Jika A×B = x² + 6x - 16 dan A×C = x² - x - 2 hasil B×C =........ HARUS MENGGUNAKAN CARA

A×B=x²+6x-16=(x-2)(x+8)
A×C=x²-x-2 = (x-2)(x+1)

Jadi A=x-2, B=x+8, C= x+1

B×C=(x+8)(x+1)=x²+x+8x+8=x²+9x+8

[tex]AB = (x - 2)(x + 8) \\ AC = (x - 2)(x + 1) \\ B = (x - 8) \hspace{1 mm} dan C = (x + 1) \\ BC = (x + 8)(x + 1) = x^2 + 9x + 8[/tex]