5log7. 7log625+ 2 log 1/16=

[tex]^{5} log(7) . ^{7} log(625) + ^{2} log( \frac{1}{16} ) \\ = ^{5} log( {5}^{4} ) + ^{2} log( {2}^{ - 4} ) \\ = 4 \times ^{5} log(5) + ( - 4) ^{2} log(2) \\ = 4(1) - 4(1) \\ = 0[/tex]