Matematika

Pertanyaan

Melalui titik (1,6) dan (7,4)

1 Jawaban

  • [tex] \frac{y - y_1}{y_2-y_1} = \frac{x-x_1}{x_2 - x_1} \\ \frac{y - 6}{4 - 6} = \frac{x-1}{7-1} \\ \frac{y-6}{-2} = \frac{x-1}{6} \\ 6(y - 6) = -2(x-1) \\ 6y - 36 = - 2x + 2 \\ 2x + 6y - 38 = 0[/tex]

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