f(2x-1)=4x^2-3x+1 a. f(x) b. f(2)

[tex]f(2x-1)=4x^2-3x+1 \\ f(2x)=4(x+1)^2-3(x+1)+1 \\ f(x)=4(\frac{x+1}{2})^2-3(\frac{x+1}{2})+1 \\ f(x)=4(\frac{x^2+2x+1}{4})-\frac{3x+3}{2}+1 \\ f(x)=x^2+2x+1-\frac{3}{2}x-\frac{3}{2}+1 \\ f(x)=x^2+\frac{1}{2}x+\frac{1}{2} \\ \\ f(2)=2^2+\frac{1}{2}(2)+\frac{1}{2}=4+1+\frac{1}{2}=\frac{11}{2}[/tex]