Matematika

Pertanyaan

2x²-6x-p=0 adalah x1 dan x2 jika x1-x2=5 nilai p adalah

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  • jawab
    Persamaan kuadrat
    2x²-6x - p = 0
    a= 2
    b = - 6
    c = -p

    x1. + x2 = - b/a =  -(-6)/2= 3
    x1. x2 = c/a = - p/2
    x1- x2 = 5

    x1 + x2 = 3
    x1 - x2 = 5 .....(+)
    2x1 = 8
    x1 = 4

    x1 + x2 = 3
    x2 = 3 - x1
    x2 = 3-4
    x2 = - 1

    x1 .x2 =  - p/2
    4(-1) = -p/2
    -4 = -p/2
    -p = 2(-4)
    p = 8


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