soal mtk cara cariknya

Integral

int 6x(1-x²)^4 dx

u = 1-x²
du/dx = -2x
dx = du/(-2x)

int 6x (u)⁴ (du/(-2x))
int -3u⁴ du
= -3/5 . u^5
= -3/5 . (1-x²)^5 + C

jawaban : A