Diket : R1 = 18 Ω (rangkaian paralel) (I1) R2 = 36 Ω (rangkaian paralel) (I2) R3 = 6 Ω (B - C rangkaian seri ) V = 6 volt R1 dan R2 (A - B) Dita : arus (I) tota

---R.pengganti = 1/18 + 1/36 = 2+1/36 = 3/36 = 12
*jadi R.pengganti = 12 ohm
---R.total = 6 ohm + 12 ohm = 18 ohm
--- I total = V/R = 6/18 = 1/3 ampere
--- Vbc = I x Rpengganti = 1/3 x 12 = 4 volt
--- Vab = I x R = 1/3 x 6 = 2 volt
--- I 1 = Vbc/R  = 4/18 =2/9 ampere
--- I 2 = Vbc/R = 4/36 = 1/9 ampere